How To Determine Limiting Reactant From Mole Ratio 2021 Guide 2022. $\begingroup$ you can already see from your first calculation that ca(no3)2 is the limiting reagent, because you had more moles of na3po4 than ca3(no3)2 and the equation tells us that 3 moles of ca3(no3)2 react with 2 moles of na3po4.(a) if the calculated moles needed is greater than the moles have for a given. According to the reactants given (16.9 g of hydrogen gas and 35.4 g of nitrogen) and the mass ratios, it's likely that the nitrogen gas is the limiting reactant.
How to determine limiting reactant given moles. $\begingroup$ you can already see from your first calculation that ca(no3)2 is the limiting reagent, because you had more moles of na3po4 than ca3(no3)2 and the equation tells us that 3 moles of ca3(no3)2 react with 2 moles of na3po4.(a) if the calculated moles needed is greater than the moles have for a given. According to the reactants given (16.9 g of hydrogen gas and 35.4 g of nitrogen) and the mass ratios, it's likely that the nitrogen gas is the limiting reactant.
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According To The Reactants Given (16.9 G Of Hydrogen Gas And 35.4 G Of Nitrogen) And The Mass Ratios, It's Likely That The Nitrogen Gas Is The Limiting Reactant.
How to determine limiting reactant given moles. $\begingroup$ you can already see from your first calculation that ca(no3)2 is the limiting reagent, because you had more moles of na3po4 than ca3(no3)2 and the equation tells us that 3 moles of ca3(no3)2 react with 2 moles of na3po4.(a) if the calculated moles needed is greater than the moles have for a given.